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December 22, 2014

December 22, 2014

Posted by **sharkman** on Saturday, February 23, 2008 at 5:52pm.

Let t = theta

(1) r = sin(t) + 1

(2) r = sin(t) - cos(t)

- Polar to Rectangular Form -
**Reiny**, Saturday, February 23, 2008 at 6:08pmWhere you not given, or does your text not have formulas for changing from polar to rectangular????

I will do the first one

r^2 = x^2 + y^2 and sin(theta) = y/r

so you have

√(x^2+y^2) = y/√(x^2+y^2) + 1

multiply each term by √(x^2+y^2)

x^2+y^2 = y + √(x^2+y^2)

try the second one yourself, cos(t) = x/r

- Polar to Rectangular Form -
**Anonymous**, Friday, February 14, 2014 at 8:11pm(3,2n/5)

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