Sunday

January 25, 2015

January 25, 2015

Posted by **Martin** on Saturday, February 23, 2008 at 5:33pm.

a. At what rate is the depth of the oil in the conical cup rising when the oil in the cup is 3 inches deep?

b. When the oilcan is empty, what is the depth of the oil in the conical cup?

Please show step-by-step work in your answers. Thanks in advance! :)

- Calculus -
**Reiny**, Saturday, February 23, 2008 at 5:50pmlet the height of oil in the cone be h in, let the radius of the surface of oil in the cone be r in. Let the volume in the cone be V in^3

by ratios: r/h = 4/8

r = h/2

given d(V)/d(time) = 2 cu inches/hour

find dh/dt when h = 3 inches

V = (1/3)pi(r^2)h subbing in r=h/2

V = (1/12)pi(h^3)

dV/dt = (1/4)pi(h^2)dh/dt

sub in dV/dt = 2 and h = 3 to get

dh/dt = 8/(9pi) inches/hour

for b)

find the volume of the cylinder.

sub that into V=(1/12)pi(h^3) and solve for h

Let me know if you got h = 6.6

- Calculus -
**Ryan**, Tuesday, January 26, 2010 at 8:44pmFor part (b), I don't understand why h = 6.6 ft because that would mean that the volume of the oilcan had a volume of 75.27 in^3. In actuality, the oilcan had a volume of 25.13 in^3, so the height should be 4.6 ft. **

- Calculus -
**Joe**, Sunday, February 21, 2010 at 10:49amRyan is wrong. Reiny is correct. h = 6.6

- Calculus -
**Anonymous**, Sunday, November 21, 2010 at 9:50pmA drum can in the shape of a rectangular shape with a square base is required to have a volume of 100 cubic feet. Draw a diagram of the drum indicating x, the side of the base and h, the height.

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