Posted by Anonymous on Saturday, February 23, 2008 at 3:29pm.
Power = V^2/R = 120^2/R = 1.44*10^4/R
Energy = power * time
where time = 10 minutes = 600 seconds = 6*10^2 s
so
Energy in Joules = (1.44*6)*10^6/R
= 8.64*10^6/R in Joules
Now, how many Joules does it take to heat the water?
Joules into water = 1.5 kg*4190 J/kg deg*(50-10) deg = 251,400 Joules = 2.51*10^5 Joules
So
8.64 *10^6 / R = 2.51 * 10^5
Don't try to find one magical formula that you just plug into to get the answer. Do the problem one step at a time and use formulas that you understand, your powers of reasoning. That is how physics and engineering is done.
The heat energy that must be added to the water is
Q = M C *(delta T)
= 1500 g*4.184 J/(g C)*40 C = 2.51*10^5 J
delta T is the temperature change and C is the specific heat of water.
To provide this much heat in T = 10 min (which is 600 s), the electrical power must be
P = Q/T = 2.51*10^5/600 = 415 J/s or watts
The last step is choosing the right resistor R, is to use
P = V^2/R, where V is the voltage and P is the required power. The answer will be in ohms.
Related Questions
Physics - what is the required resistance of an immersion heater that will ...
Physics - what is the required resistance of an immersion heater that will ...
physics - What is the required resistance of an immersion heater that will ...
Physics - An electric immersion heater is rated 5 A when connected to a 120V ...
Physics - The recovery time of a hot water heater is the time required to heat ...
physics - The recovery time of a hot water heater is the time required to heat ...
Physics - A small electric immersion heater is used to boil 191.0 g of water for...
Physics - A small electric immersion heater is used to boil 191.0 g of water for...
Physics - #1.) A wind turbine has a Cp of 0.42 and extracts 50 kW of power when ...
Physics - An immersion heater of resistance R converts electrical energy into ...
For Further Reading
