How to find the solution set in a+bi form for this equation?
6x^2+4x+1=0
PLEASE HELP!THANKS!!!!
Use the quadratic equation. In your case the constants are a=6, b=4 and c=1.
x = -b +/-sqrt(b^2-4ac)]/12
The b^2 - 4ac term is negative, and that will provide the imaginary term.
x = [-4 +/-sqrt(-8)]/12 = -1/3 +/- (sqrt2)/6 i