Posted by **Jon** on Friday, February 22, 2008 at 1:42pm.

1)If y varies inversely as x and y = 3, when x = 6. Find y when x = 36.

A)72

B)2

C)1/2

D)18

I chose C

y1/x2 = y2/x1

3/36 = y2/6

18/36 = 1/2

2)Write the equation 4^-3 = 1/64 in logarithmic form.

A)log64 = 4^3

B)log^-3 64 = 4

C)log^4 1/64 = -3

D)log^4(-3) = 64

I chose C

3)Solve: 6^n+1 >= 10. Round to four decimal places.

A)n >= 0.2851

B)n >= 0.6667

C)n >= 1.2851

D)n >= -0.7782

I chose C

log10/log6

1.2851

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