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July 22, 2014

July 22, 2014

Posted by **sarah** on Friday, February 22, 2008 at 12:23am.

if the sum of asubn from n=1 to infinity converges, and if a is not equal to 0, the the sum of 1/(a sub n) as n goes from 1 to infinity diverges.

- calculus -
**drwls**, Friday, February 22, 2008 at 7:23amTrue.

In order for the a subn series to converge, an infinite number of terms past some n value must be <0 , individually. That means there must be an infinite number of terms >0 in the 1/asubn series. Therefore it cannot converge.

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