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April 20, 2014

April 20, 2014

Posted by **sarah** on Thursday, February 21, 2008 at 7:56pm.

it is the sum from k=1 to infinity of ((-1)^k)/(3^(k+1))

i found this series to be geometric where

a=-1/9 and

r=1/3

my answer was converges to 1/6

- calculus -
**Damon**, Thursday, February 21, 2008 at 8:56pm(-1)^k

---------

3^(k+1)

-1/9 , 1/27 , -1/3^4 ...

yes, g = -1/9

no r = -1/3 (disagree with your sign)

Sum = -(1/9 ) / (1 +1/3) =-1/12

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