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January 24, 2015

January 24, 2015

Posted by **NIck** on Thursday, February 21, 2008 at 7:29pm.

- statistics -
**Damon**, Thursday, February 21, 2008 at 8:20pmThis is a binomial distribution with p = 1/2 and n = 16

p

mean = n p = 8

sigma^2 = n p(1-p) = 16*(1/2)(1/2) = 4

so sigma = 2

to get probability of k trues (or false since p = 1/2 and therefore 1-p also = 1/2

P(k) = C(n/k)* p^k *(1-p)^(n-k)

C(n/k) is "binomial coef. Look it up in table or use Pascal's triangle or use

C(n/k) = n!/[k!(n-k)!]

In our case (1/2 is much easier than any other)

p^k * (1-p)^(n-k) =(1/2)^k * (1/2)^(16-k) = (1/2)^16 = 1/65536

our C(16/k) values are

1 16 120 560 1820 4368 8008 11440 12870 11440 8008 4368 1820 560 120 16 1

note that the first value, 1, is for n = 16, k = 0

so for example the probability of 6 true is 8008/65536 = .122

P(4) = 1820

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