in a soda-acid fire extinguisher, concentrateed sulfuric acid reacts with sodium hydrogen carbonate to produce carbon dioxide, sodium sulfate and water. How many moles of sodium hydrogen carbonate would be neefed to react with 150.0 grams of sulfuric acid? How many moles of each product are formed?

To find the number of moles of sodium hydrogen carbonate needed to react with 150.0 grams of sulfuric acid, you need to use the molar ratios from the balanced chemical equation.

The balanced chemical equation for the reaction is:
H2SO4 + 2NaHCO3 → Na2SO4 + 2CO2 + 2H2O

From the equation, you can see that one mole of sulfuric acid (H2SO4) reacts with two moles of sodium hydrogen carbonate (NaHCO3).

To find the number of moles of sodium hydrogen carbonate, you will need to calculate the molar mass of sulfuric acid.

The molar mass of sulfuric acid (H2SO4) is:
2(1.008 g/mol) + 32.06 g/mol + 4(16.00 g/mol) = 98.09 g/mol

Using the molar mass of sulfuric acid, you can calculate the moles of sulfuric acid in 150.0 grams:

Moles of sulfuric acid = mass of sulfuric acid / molar mass of sulfuric acid
Moles of sulfuric acid = 150.0 g / 98.09 g/mol ≈ 1.53 mol

Since the molar ratio between sulfuric acid and sodium hydrogen carbonate is 1:2, the number of moles of sodium hydrogen carbonate needed is twice that of sulfuric acid.

Moles of sodium hydrogen carbonate = 1.53 mol × 2 = 3.06 mol

Therefore, you would need approximately 3.06 moles of sodium hydrogen carbonate to react with 150.0 grams of sulfuric acid.

Now, let's calculate the number of moles of each product formed.

From the balanced equation, you can see that for every one mole of sodium hydrogen carbonate that reacts, you get one mole of sodium sulfate (Na2SO4), two moles of carbon dioxide (CO2), and two moles of water (H2O) as products.

Therefore, the number of moles of each product formed would be:

Moles of sodium sulfate = Moles of sodium hydrogen carbonate = 3.06 mol
Moles of carbon dioxide = 2 × Moles of sodium hydrogen carbonate = 2 × 3.06 mol = 6.12 mol
Moles of water = 2 × Moles of sodium hydrogen carbonate = 2 × 3.06 mol = 6.12 mol

Hence, approximately 3.06 moles of sodium hydrogen carbonate are needed to react with 150.0 grams of sulfuric acid, and 6.12 moles of each product (sodium sulfate and water) are formed, while 6.12 moles of carbon dioxide are also produced.