let s= the sum of all even numbers from 2 to 10 {including 2 and 10}
Let t= the sum of all odd numbers from 1 to 9 z{including 1 and 9.. find s-t
LOL
2 - 1 = 1
4 - 3 = 1
...............
...............
10 - 9 = 1
get it ?
s = 2 + 4 + 6 + 8 + 10
s = 30
t = 1 + 3 + 5 + 7 + 9
t = 25
Then:
s - t = 30 - 25
s - t = 5
Done!
THANX THAT ANSWER WAS WELL EXPLAINED AN EVERYTHING
LOL, yes 5*1 = 5 !!!
To find the value of s-t, we first need to calculate the sum of the even numbers from 2 to 10 and the sum of the odd numbers from 1 to 9.
To calculate the sum of a series of consecutive numbers, we can use the formula: sum = (n/2) x (first number + last number), where n is the number of terms in the series.
For the even numbers:
The first even number is 2, and the last even number is 10. So the number of terms, n, is 5.
sum of even numbers = (5/2) x (2 + 10) = 5 x 12 = 60
For the odd numbers:
The first odd number is 1, and the last odd number is 9. So the number of terms, n, is 5.
sum of odd numbers = (5/2) x (1 + 9) = 5 x 10 = 50
Now we can find s-t by subtracting the sum of odd numbers from the sum of even numbers:
s - t = 60 - 50 = 10
Therefore, s - t = 10.