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November 22, 2014

November 22, 2014

Posted by **kay** on Wednesday, February 20, 2008 at 6:13pm.

Okay, 18 heads = 18 animals my question is how do I go about finding this?

- Pre-Algebra -
**kay**, Wednesday, February 20, 2008 at 6:28pmShould I just do it randomly? Like first try 16 chickens and go on from there? Surely there is a simpler way to do this since a bigger problem wouldn't work this way.

- Pre-Algebra -
**Reiny**, Wednesday, February 20, 2008 at 7:29pmlet the number of chickens be x

and the number of rabbits be y

so x+y = 18 and 2x + 4y = 58, divide this last equation by 2 to get x+2y=29

then

x+2y=29

x+ y=18 ..... subtract them

y=11, subbing back x = 7

7 chicken and 11 rabbits

check: 18 animals, so 18 heads

7chicken have 14 feet, 11 rabbits have 44 feet, so 14+44 = 58 feet

- Pre-Algebra -
**kay**, Wednesday, February 20, 2008 at 10:49pmThank you!!

- Pre-Algebra -
**Bob Smith**, Wednesday, February 1, 2012 at 10:44pmThere are 7 chickens- 14 Chicken feet.

There are 11 rabbits- 44 chicken feet.

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