HELP! we just started kinetics and i have no clue how to solve this problem.
For the reaction between reactants A and B below, if 4.925 moles of A is placed into a flask with excess B it is found that the amount of A remaining after 6.85 seconds is 2.737 moles.
2A (g) + B (g)-----> 3 C (g)
a. find the rate of reaction with respect to A (in Ms^-1)
b. find the rate of the reaction with respect to B
c. find the reate of the reaction with respect to C
i'm really struggling with learning kinetics. :[
thank you.
I can help you with this kinetics problem! To find the rate of reaction with respect to each reactant and product, we need to use the concept of reaction rates and stoichiometry. Let's break it down step by step:
a. To find the rate of reaction with respect to A, we need to determine the change in the concentration of A over time. We are given that the initial moles of A is 4.925 moles, and after 6.85 seconds, the remaining amount is 2.737 moles. The change in concentration of A can be calculated as:
Change in concentration of A = Initial concentration of A - Final concentration of A
Concentration = Moles / Volume
So, the initial concentration of A is 4.925 moles divided by the volume of the flask, and the final concentration of A is 2.737 moles divided by the same volume. Since we have excess B, the change in moles of A will be equal to the moles of A reacting.
Rate of reaction with respect to A = Change in concentration of A / Time
To find the units of rate, we divide the concentration unit (moles/volume) by the time unit (seconds):
Rate of reaction with respect to A = (mol/volume) / seconds
b. Similarly, we can find the rate of reaction with respect to B using the stoichiometry of the balanced equation. From the balanced equation, we see that the stoichiometric coefficient of B is 1. Therefore, the rate of reaction with respect to B is the same as the rate of reaction with respect to A. The units will be (mol/volume) / seconds as well.
c. To find the rate of the reaction with respect to C, we use the stoichiometry again. From the balanced equation, we see that the stoichiometric coefficient of C is 3. This means that for every 2 moles of A reacting, we produce 3 moles of C. So, the rate of reaction with respect to C will be:
Rate of reaction with respect to C = (3 / 2) * Rate of reaction with respect to A
In terms of units, it will be (3 / 2) * [(mol/volume) / seconds].
By following these steps and using the stoichiometry of the balanced equation, you can find the rates of reaction with respect to A, B, and C. Just remember to use the appropriate concentration units and consider the stoichiometry when converting between reactants and products.