Posted by Jon on Wednesday, February 20, 2008 at 11:55am.
Which describes the number and type of roots of the equation x^2625=0?
A)1 real root, 1 imaginary root
B)2 real roots, 2 imaginary roots
C)2 real roots
D)4 real roots
I went with A
sqrt x^2= x (which would be the imaginary) and sqrt 625= 25 (the real)

Math  Reiny, Wednesday, February 20, 2008 at 12:09pm
How did you get that answer???
This is a straightforward difference of squares setup
(x+25)(x25) = 0
so x = ± 25
2 real roots, so C

Math(I see that now)  Jon, Wednesday, February 20, 2008 at 12:14pm
I made it harder than it was thanks. But I just thought that x was imaginary

Math  Damon, Wednesday, February 20, 2008 at 1:39pm
By the way, if you get one complex or imaginary root, you get two. They come in pairs, like male and female twins. One has +imaginary number, the other has the same imaginary number. They are called complex conjugates. a + b i and a  b i and a can be zero.
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