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Which describes the number and type of roots of the equation x^2-625=0?

A)1 real root, 1 imaginary root
B)2 real roots, 2 imaginary roots
C)2 real roots
D)4 real roots
I went with A

sqrt x^2= x (which would be the imaginary) and sqrt 625= 25 (the real)

  • Math - ,

    How did you get that answer???

    This is a straightforward difference of squares setup

    (x+25)(x-25) = 0

    so x = ± 25

    2 real roots, so C

  • Math(I see that now) - ,

    I made it harder than it was thanks. But I just thought that x was imaginary

  • Math - ,

    By the way, if you get one complex or imaginary root, you get two. They come in pairs, like male and female twins. One has +imaginary number, the other has -the same imaginary number. They are called complex conjugates. a + b i and a - b i and a can be zero.

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