Homework Help: Math

Posted by Jon on Wednesday, February 20, 2008 at 11:55am.

Which describes the number and type of roots of the equation x^2-625=0?

A)1 real root, 1 imaginary root
B)2 real roots, 2 imaginary roots
C)2 real roots
D)4 real roots
I went with A

sqrt x^2= x (which would be the imaginary) and sqrt 625= 25 (the real)

Math - Reiny, Wednesday, February 20, 2008 at 12:09pm
How did you get that answer???

This is a straightforward difference of squares setup

(x+25)(x-25) = 0

so x = ą 25

2 real roots, so C
Math(I see that now) - Jon, Wednesday, February 20, 2008 at 12:14pm
I made it harder than it was thanks. But I just thought that x was imaginary
Math - Damon, Wednesday, February 20, 2008 at 1:39pm
By the way, if you get one complex or imaginary root, you get two. They come in pairs, like male and female twins. One has +imaginary number, the other has -the same imaginary number. They are called complex conjugates. a + b i and a - b i and a can be zero.

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