Posted by Jon on Wednesday, February 20, 2008 at 11:22am.
Find the exact solution to 6x^2+1=8x by using the Quadratic Formula.
A)4+(sqrt10)
B)4+(sqrt22)/6
C)2+2(sqrt10)/3
D)4+(sqrt10)/6
I chose C
x=b+(sqrtb^24ac)/2a
x=8+(sqrt8^24(6)(1))/2(6)
x=8+(sqrt6424)/12
x=8+(sqrt40)/12
x= C

Math  Reiny, Wednesday, February 20, 2008 at 11:32am
correct

Math  drwls, Wednesday, February 20, 2008 at 11:40am
In the first one a = 6, b = 8 and c = 1
x = [8 +sqrt (6424)]/12
=[8 +sqrt(4*10)]/12
=[8 +2sqrt(10)]/12
=[4 +sqrt10]/6
So your amswer is wrong.

Math(im confused)  Jon, Wednesday, February 20, 2008 at 12:50pm
Please explain x = [8 +sqrt (6424)]/12
=[8 +sqrt(4*10)]/12

Math  drwls, Wednesday, February 20, 2008 at 1:03pm
64  24 = 40 = 4*10

Math(please explain b/c I don't think im wrong)  Jon, Wednesday, February 20, 2008 at 1:07pm
I did all the steps

Math  Damon, Wednesday, February 20, 2008 at 1:28pm
a = 6
b = 8
c = 1
why did you use 8 for b?
why dis you not divide b by 2a?
you left a bracket out, wrecking everything
x = [ 8 +/ sqrt (64  4*6*1) ] /2*6
x = [ 8 +/ sqrt(6424) ] / 12
x = [ 8 +/ sqrt (4*10) ] /12
x = [ 8 +/ 2 sqrt (10) ] / 12
x = [ 4 +/ sqrt(10) ] / 6
I agree with drwls :)
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