Find the exact solution to 6x^2+1=-8x by using the Quadratic Formula.
A)-4+-(sqrt10)
B)-4+-(sqrt22)/6
C)-2+-2(sqrt10)/3
D)-4+-(sqrt10)/6
I chose C
x=-b+-(sqrtb^2-4ac)/2a
x=--8+-(sqrt-8^2-4(6)(1))/2(6)
x=8+-(sqrt64-24)/12
x=8+-(sqrt40)/12
x= C
correct
In the first one a = 6, b = 8 and c = 1
x = [-8 +-sqrt (64-24)]/12
=[-8 +-sqrt(4*10)]/12
=[-8 +-2sqrt(10)]/12
=[-4 +-sqrt10]/6
So your amswer is wrong.
Thanks for picking up on that
As George would have said,
"I guess I mislooked"
Please explain x = [-8 +-sqrt (64-24)]/12
=[-8 +-sqrt(4*10)]/12
64 - 24 = 40 = 4*10
I did all the steps
i don't understand
a = 6
b = 8
c = 1
why did you use -8 for b?
why dis you not divide -b by 2a?
you left a bracket out, wrecking everything
x = [ -8 +/- sqrt (64 - 4*6*1) ] /2*6
x = [ -8 +/- sqrt(64-24) ] / 12
x = [ -8 +/- sqrt (4*10) ] /12
x = [ -8 +/- 2 sqrt (10) ] / 12
x = [ -4 +/- sqrt(10) ] / 6
I agree with drwls :)
Which don't you understand:
64-24 = 40, or
40 = 4 x 10?
Or my use of * for x when multiplying?
We do that often here to avoid confusion with the algebraic variable x.
To find the exact solution to the quadratic equation 6x^2 + 1 = -8x using the quadratic formula, follow these steps:
Step 1: Identify the coefficients a, b, and c from the given equation. In this case, a = 6, b = -8, and c = 1.
Step 2: Substitute the values of a, b, and c into the quadratic formula:
x = (-b ± √(b^2 - 4ac)) / (2a)
Step 3: Plug in the values from step 1 into the quadratic formula:
x = (-(-8) ± √((-8)^2 - 4(6)(1))) / (2(6))
Step 4: Simplify the expression inside the square root:
x = (8 ± √(64 - 24)) / 12
x = (8 ± √40) / 12
Step 5: Simplify the expression further:
x = (8 ± 2√10) / 12
Step 6: Simplify the expression by dividing both the numerator and denominator by the greatest common divisor, which is 4 in this case:
x = (2(4 ± √10)) / (4(3))
x = (4 ± √10) / 6
The correct solution is option C: -2 ± 2√10/3.