hello, can you help me to solve this question?
x^2+9>0
thank you''
(x+3)(x-3)>0
which means x cannot be 3, or -3
Then test to see if the inequality is good for -inf<x<-3, from -3<x<3, and from 3<x<inf
bobpursley,
How can you factor x^2 + 9 into
(x - 3) (x + 3) when there is a PLUS sign between x^2 and the constant 9?
Get my point?
Of course, I can help you with that! To solve the inequality x^2 + 9 > 0, we need to find the values of x that make the inequality true.
Step 1: Note that x^2 is always non-negative (or zero), regardless of the value of x, since squaring any real number gives a positive result.
Step 2: Next, observe that 9 is a positive number.
Step 3: Combining steps 1 and 2, we can conclude that the left-hand side of the inequality (x^2 + 9) is always greater than zero, since the non-negative x^2 term will ensure this.
Step 4: Therefore, the inequality x^2 + 9 > 0 is true for all real numbers of x. In other words, any real number will satisfy this inequality.
So, the solution to the inequality x^2 + 9 > 0 is the set of all real numbers, or (-∞, +∞).
I hope that helps! Let me know if you have any further questions.