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April 16, 2014

April 16, 2014

Posted by **kelly** on Tuesday, February 19, 2008 at 11:24pm.

csc x-sin x to cot x cos x

- trig -
**drwls**, Tuesday, February 19, 2008 at 11:45pmcsc x-sin x = (1/sinx) - sin x

= (1 - sin^2 x)/sin x = (cos x * cos x)/sin x

= cos x cot x

- trig -
**Guido**, Wednesday, February 20, 2008 at 5:29pmWe have trig identities.

cscx - sinx to cotx(cos x).

cscx is the reciprocal of the sine function.

So, then:

cscx = 1/sinx

We now have:

1/sinx - sinx...Treat this like a fraction case.

1/sinx - sinx becomes (1 - sin^2x)/sinx

Of course, (1 - sin^2x) is one of the Pythagorean Identities, recall?

We know that (1 - sin^2x) = cos^2x

We now have:

cos^2x/sinx = the right side

Done!

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