Posted by kelly on Tuesday, February 19, 2008 at 11:24pm.
transform the expression on left to one on right
csc x-sin x to cot x cos x
trig - drwls, Tuesday, February 19, 2008 at 11:45pm
csc x-sin x = (1/sinx) - sin x
= (1 - sin^2 x)/sin x = (cos x * cos x)/sin x
= cos x cot x
trig - Guido, Wednesday, February 20, 2008 at 5:29pm
We have trig identities.
cscx - sinx to cotx(cos x).
cscx is the reciprocal of the sine function.
cscx = 1/sinx
We now have:
1/sinx - sinx...Treat this like a fraction case.
1/sinx - sinx becomes (1 - sin^2x)/sinx
Of course, (1 - sin^2x) is one of the Pythagorean Identities, recall?
We know that (1 - sin^2x) = cos^2x
We now have:
cos^2x/sinx = the right side
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