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December 21, 2014

December 21, 2014

Posted by **Anonymous** on Tuesday, February 19, 2008 at 9:47pm.

My work, using geometric vectors:

| r |^2 = 90^2 + 90^2 - 2(90)(90)cos132

| r | = 164.4 N

sin132 / 164.4 = sinx / 90

x = 24 degrees

Therefore the resultant force is 164.4 N, 24 degrees from 90 N.

*************MY QUESTION*********

-------- How do I find the equilibrium to this problem? Can you please provide a step by step solution?

Thanks

- Math: Calculus - Vectors -
**Damon**, Tuesday, February 19, 2008 at 10:08pmI assume you did the law of cos and of sin right, not checking

To hold this force in equilibrium, you need a force equal and magnitude and opposite in direction to the resultant.

so 164.4 N at 180+24 = 204 degrees from one of the original 90 N forces.

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