Posted by physics..... on Tuesday, February 19, 2008 at 2:54pm.
1500W thingy heats1.5kg water from 18C to 59C in 3.0minutes. How mcuh nergy was used by the thingy?

physics.  drwls, Tuesday, February 19, 2008 at 3:02pm
There are two ways to do this and they should agree, if all of the electrical power goes into heating the water. Let's see if they do.
Power consumed by the "thingy" is 1500 J/s * 3.0 min * 60 s/min = 270,000 J
Q = Change of water's internal energy
= m C *delta T
= 1500 g* (1.0 cal g/C)*41 C *4.18 J/cal= 257,070 J
The latter number is more reliable. The 1500 W rating of the heater may have not been quite been reached due to low voltage, or heat transferred to other regions
Answer This Question
Related Questions
 physics.  a 1500W thing heats 1.5kg of water from 18C 59C in 3 minutes. how ...
 Algebra 2  Can someone please assist me with this? (9/49)^(3/2) I do this ...
 algebra 1  in the equation thingy for y=mx+b how do you solve for b?
 6th grade math  1.50.but can you explain more detailed about the 0.2 thingy.
 Calculus  Evaluate the definite integral The S thingy has 1 at the bottom and 9...
 Math  what is a set? what are these domain stuff thingy? i am unable to ...
 Math  The square root with tha dash and slant thingy is between what two ...
 Biology  Hi I need help Interphase: Describe the traits of the chromosomes at ...
 Calculus 2 II  integral from 0 to 1 of x4/(x^25x+6) I do believe we can ...
 Mathematics  For what values of m and n Does the expression ( mx^4 + nx^3 + 14x...
More Related Questions