Homework Help: Brad

Posted by Chemistry on Tuesday, February 19, 2008 at 1:33pm.

My problem is calculate the molarity of HCl and NaOH
(molarity of acid)x(volume of acid)=(molarity of base)+(volume of added base)
HCl=acid NaOH=base
HCl volume = 25mL=0.025L
NaOH=67.05mL=0.06705
molarity = moles of solute
Liters of a solution
M=0.015000 moles of NaOH
0.06705L
M1V1=M2V2
M1V1=M2V2
V1
M1=M2V2
V1
M1=0>223713647 M of NaOH * 0.06705L
0.025L
M1=0.600000001M of HCl

0.600000001 M of HCl* 0.025L =
0.223713647 M of NaOH * 0.06705L

Am I even close?

No one has answered this question yet.

Answer this Question

Related Questions

Chemistry - Calculate the molarity of the HCl from the volumes of acid and base ...
Chemistry - Can someone please tell me if I did this correctly? Calculate the ...
chemistry - My problem is calculate the molarity of HCl and NaOH. (molarity of ...
chemistry - I am confused on how to do the last question. Calculate molarity of ...
chemistry - The following data were collected at the endpoint of a titration ...
chemistry - acid: HCI 0.10 M Base:NaOH O.050 M 3 ml of HCI was used. Calculate ...
chemistry - 1. if 15.0mL of 4.5 M NaOH are diluted with water to a volume of ...
Chemistry - Volume of HCl, mL:26.5mL Volume of NaOH,mL:29.1mL Molarity of NaOH, ...
Chemistry - 1) You are given solutions of HCl and NaOH and must determine their ...
college - 1) You are given solutions of HCl and NaOH and must determine their ...

For Further Reading

First Name:
School Subject:
Answer: