posted by Chemistry on .
My problem is calculate the molarity of HCl and NaOH
(molarity of acid)x(volume of acid)=(molarity of base)+(volume of added base)
HCl volume = 25mL=0.025L
molarity = moles of solute
Liters of a solution
M=0.015000 moles of NaOH
M1=0>223713647 M of NaOH * 0.06705L
M1=0.600000001M of HCl
0.600000001 M of HCl* 0.025L =
0.223713647 M of NaOH * 0.06705L
Am I even close?