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January 30, 2015

January 30, 2015

Posted by **Jon** on Tuesday, February 19, 2008 at 1:03pm.

A)2;between 0 and 1

B)between 0 and 1;between 7 and 8

C)1,2

D)between 0 and 1;between 3 and 4

I don't understand this one either its gotta be A or C I don't undertand what I got from a website which gave me X1=2 and X2=.6 repeating

- math -
**Reiny**, Tuesday, February 19, 2008 at 1:28pmlet y = 3x^2-8x+4 or f(x) = 3x^2-8x+4 , same thing

try a few x's

I tried -1,0,1,2,3 and y values of

15,4,-1,0,7

notice when x = 0 the graph is above the x-axis, but when x=1 the graph is below the x-axis.

So there has to be a solution between x=0 and x=1

Also notice when x=2 , y =0, so x=2 is a solution.

**Solutions to equations are where the matching graph cuts the x-axis.**

Now that we know that we have an exact solution at x=2, x-2 must be an exact factror, and sure enough

3x^2-8x+4 = (x-2)(3x-2)

so x=2 or x=2/3

- math -
**Jon**, Tuesday, February 19, 2008 at 1:41pmSo C would be the choice?

- math -
**Reiny**, Tuesday, February 19, 2008 at 1:59pmNOOO, it is A

Did you not read when I said:

"notice when x = 0 the graph is above the x-axis, but when x=1 the graph is below the x-axis.

So there has to be a solution between x=0 and x=1

Also notice when x=2 , y =0, so x=2 is a solution. "

- math(typo) -
**Jon**, Tuesday, February 19, 2008 at 2:08pmOh yeah duh. my mistake

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