Posted by Anonymous on Tuesday, February 19, 2008 at 11:04am.
An oscillating pendulum, or anything else in nature that involves "simple harmonic" (sinusoidal) motion, spends 1/4 of its period going from zero speed to maximum speed, and another 1/4 going from maximum speed to zero speed again, etc. After four quarter-periods it is back where it started. In your case the period is 1/f = 2 pi sqrt (L/g) = 1.62 s
One-quarter of that is 0.405 s
That is the answer.
How did you get 1.62 s?
Nevermind, I got it. Thank you!
Related Questions
physics - A tetherball leans against the smooth, frictionless post to which it ...
physics - A tetherball leans against the smooth, frictionless post to which it ...
Physics - A ball on the end of a string is moving in circular motion as a ...
Physics...... - A ball on a 6.5 m long string swings down and wraps around a ...
Physics - A ball on a 6.5 m long string swings down and wraps around a post that...
physics - A ball is attached to the moving end of the 5-meter arm of a pendulum...
Physics - I am not sure how to setup this problem. I posted it earlier and "...
physics - I am not sure how to setup this problem. I posted it earlier and "...
physics - A ball(mass=3kg) is attached to 2 strings and it is rotated by one ...
physics - 3. A 250-g is attached to a string 1.00 m long to make a pendulum. If ...
For Further Reading