Post a New Question

Physical science

posted by .

When you drop a 0.36 kg apple, Earth exerts a force on it that accelerates it at 9.8 m/s^2 toward the earth's surface. According to Newton's third law, the apple must exert an equal but opposite force on Earth. If the mass of the earth 5.98x10^24 kg, what is the magnitude of the earth's acceleration toward the apple? (the answer must be in units of m/s^2)

I tried this and used F=ma
(.36)(9.8) = (5.98x10^24)(a)
so a= 5.899x10^-25
But my answer was incorrect. Can someone tell me how to solve this problem and what I did wrong?

  • Physical science -

    What exactly do you think is wrong with your answer. Roughly in my head I agree with you, about 6*10^-25 m/s^2

  • Physical science -

    A 50.0 kg object is lifted using 4900.0 J. How high is it lifted?

Answer This Question

First Name:
School Subject:

Related Questions

More Related Questions

Post a New Question