Posted by Amelie on Sunday, February 17, 2008 at 2:23pm.
A certain pizza restaurant offers three different sizes of pizza and eight different toppings.
How many distinct pizzas having two different toppings can be made?
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I think part of the answer to the question is
(8)\
(2)/ where I choose 2 toppings from 8.
==> 8!/ (6!* 2!)= 28
But im not sure what to do from there, if it's correct.

Intro to probability  Reiny, Sunday, February 17, 2008 at 2:36pm
ok so far.
Wouldn't those 28 ways also be available in each of the 3 sizes of pizza?
so final number of ways = 3x28 = 84

Intro to probability  Amelie, Sunday, February 17, 2008 at 2:44pm
oh, now wasn't that simple, thank you reiny
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