Posted by **Amelie** on Sunday, February 17, 2008 at 2:23pm.

A certain pizza restaurant offers three different sizes of pizza and eight different toppings.

How many distinct pizzas having two different toppings can be made?

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I think part of the answer to the question is

(8)\

(2)/ where I choose 2 toppings from 8.

==> 8!/ (6!* 2!)= 28

But im not sure what to do from there, if it's correct.

- Intro to probability -
**Reiny**, Sunday, February 17, 2008 at 2:36pm
ok so far.

Wouldn't those 28 ways also be available in each of the 3 sizes of pizza?

so final number of ways = 3x28 = 84

- Intro to probability -
**Amelie**, Sunday, February 17, 2008 at 2:44pm
oh, now wasn't that simple, thank you reiny

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