math
posted by Ashley .
The area of a right triangle is 44m squared. Find the lengths of its legs if one of the legs is 3m longer than the other.

(1/2)x(x+3) = 44
x is the shorter of the two legs
x^2 + 3x 88 = 0
That factors easily. (Think 11 x 8)
Take the positive root. 
Formula needed is:
A = 1/2(base)(height)
44 = 1/2(x + 3)(x)
One leg is 3m longer than the other can be expressed as (x + 3).
The other leg is simply the letter (x).
In other words, (x + 3) is one of the legs and the letter (x) is the other leg.
This is your equation:
44 = 1/2(x + 3)(x)
Can you solve for x?
If not, write back and I will help you.