Posted by **Ashley** on Sunday, February 17, 2008 at 1:14pm.

The area of a right triangle is 44m squared. Find the lengths of its legs if one of the legs is 3m longer than the other.

- math -
**drwls**, Sunday, February 17, 2008 at 1:18pm
(1/2)x(x+3) = 44

x is the shorter of the two legs

x^2 + 3x -88 = 0

That factors easily. (Think 11 x 8)

Take the positive root.

- math -
**Guido**, Sunday, February 17, 2008 at 1:19pm
Formula needed is:

A = 1/2(base)(height)

44 = 1/2(x + 3)(x)

One leg is 3m longer than the other can be expressed as (x + 3).

The other leg is simply the letter (x).

In other words, (x + 3) is one of the legs and the letter (x) is the other leg.

This is your equation:

44 = 1/2(x + 3)(x)

Can you solve for x?

If not, write back and I will help you.

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