Can someone tell me if I am any where close or if I need to start over.
When your acetic acid reacted with the sodium hydroxide, what are the two products that were formed?
When acetic acid reacts with sodium hydroxide the two products that are formed are a water and a carboxylic acid salt (or a carboxylate ion and the metal ion from the base). These are formed because the sodium hydroxide completely neutralizes the acetic acid since it has such a strong base.
"and a carboxylic acid salt (or a carboxylate ion and the metal ion from the base)"... You could name the salt and/or the ions for a more complete answer, but otherwise this looks OK.
To determine if you are on track or need to start over, you can follow these steps:
1. Write down the balanced chemical equation for the reaction between acetic acid (CH3COOH) and sodium hydroxide (NaOH).
CH3COOH + NaOH → H2O + CH3COONa
2. Analyze the equation to identify the two products formed.
The two products are water (H2O) and sodium acetate (CH3COONa), also referred to as a carboxylic acid salt or carboxylate ion (CH3COO-) and the metal ion from the base (Na+).
3. Compare your answer with the correct one.
The correct answer is: water and a carboxylic acid salt (or a carboxylate ion and the metal ion from the base). This matches the products you mentioned, so you are on the right track!
Keep in mind that performing actual experiments and testing for the presence of these products can help confirm your results.