Posted by Jon on Friday, February 15, 2008 at 5:53pm.
First of all, x/2 will be in the second quadrant, since x is in the fourth quadrant. The sine of x/2 will therefore be positive.
Use the formula for sin (x/2) in terms of cos x.
sin(x/2) = sqrt([1-cos(x)]/2) = sqrt (1/6) = sqrt6/6
You got the right answer, but you it ssmes to have been a lucky guess.
Cos x is NOT always positive, but it is in this case.
Thank you. It wasnt really a guess it was either C or D and then I just knew it was positive so that just leaves C.
Jon,
Perhaps it would help if you drew an x-y axis system with a unit radius vector in each of the four quadrants.
then in quadrant 1
sin T = y/1 so +
cos T = x/1 so -
tan T = y/x so +
then in quadrant 2
sin T = y/1 so +
cos T = x/1 so - because x is - in q 2
tan T = y/x so -
then in quadrant 3
sin T = y/1 so -
cos T = x/1 so -
tan T = y/x so + because top and bottom both -
then in quadrant 4
sin T = y/1 so -
cos T = x/1 so +
tan T = y/x so -
sin has same sign as its inverse csc
cos has same sign as its inverse sec
tan has same sign as its inverse ctan
then in quadrant 1
sin T = y/1 so +
cos T = x/1 so +
tan T = y/x so +
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