Saturday

January 31, 2015

January 31, 2015

Posted by **Marysvoice** on Friday, February 15, 2008 at 5:07pm.

what dimentions would yield the maximum area?

What dimentions would yeild the minimum area?

- Quadratic equations -
**Reiny**, Friday, February 15, 2008 at 5:09pmA rectangle of largest area is a square.

So divide your perimeter by 4.

To build a room of minimum area is a rather silly question.

- Quadratic equations -
**Marysvoice**, Friday, February 15, 2008 at 6:44pmI apologize for my silly question. I followed your advice, revised my question and found my answer. Thank you.

- Quadratic equations -
- Quadratic equations -
**Damon**, Friday, February 15, 2008 at 6:07pmx = length

y = width

A = x y

x+y=140

A = x(140-x)

A = 140 x - x^2

look at shape of parabola by completing the square

x^2 -140 x = -A

x^2 - 140 x + 4900 = -A + 4900

(x-70)^2 = -A + 4900

the vertex will be at x = 70 and A = 4900 and the -A means that the parabola opens down (sheds water) so that vertex is the maximum where x = y =70 as Reiny told you.

since a negative x or y does not make much sense, the area may not get any smaller than zero when x --> 0 or y -->0 0

**Answer this Question**

**Related Questions**

Algebra - A carpenter is building a rectangular room with a fixed perimeter of ...

college Algebra - This is my problem: A carpenter is building a rectangular room...

Algebra 2 - A rancher is fencing off a rectangular area with a fixed perimeter ...

MATH - FIND THE PERIMETER AND AREA OF A ROOM WITH THESE DIMENTIONS 11FT 13FT ...

math 12 - A)a shed, in the shape of a square based prism, is to have volume ...

math - if you have to build a pool of 72 yards in your yard,and the construction...

College Algebra - Translate the problem into a pair of linear equations in two ...

calculus - A farmer has 180 feet of fence and wants a pen to adjoin to the whole...

math - If the numerical values of the perimeter and the area of a square are ...

Math - If you get to pick a shape of a 20 mile perimiter what shape would be ...