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July 28, 2014

July 28, 2014

Posted by **jason** on Friday, February 15, 2008 at 12:23am.

I am struggling to solve this two variable word problem.

please help.

- math -
**drwls**, Friday, February 15, 2008 at 1:39amC be Cathy's age now and B be Byte's age now.

B+4 = (3/4) (C+4) = (3/4) C + 3

B-4 = (1/2) (C-4) = (1/2) C - 2

Subtract the two equations (left and right sides separately)

8 = (1/4) C + 5

C/4 = 3

C = 12

Use either of the first equations to get B.

- math -
**jason**, Friday, February 15, 2008 at 2:43amin B+4 = (3/4) (C+4) = (3/4) C + 3

B-4 = (1/2) (C-4) = (1/2) C - 2

may I ask where you got the +3 and -2?

- math -
**eg**, Friday, February 15, 2008 at 3:50amthe +3 comes from...

(3/4)*(c+4)

which is another way of saying

((3/4)*c)+(3/4*4)

or

3/4C+(12/4)

3/4C+3

The -2 comes from multiplying 1/2 *(c-4) which is 1/2C-4/2 or simply 1/2c-2

- math -
- math -
**eg**, Friday, February 15, 2008 at 3:48amthe +3 comes from...

(3/4)*(c+4)

which is another way of saying

((3/4)*c)+(3/4*4)

or

3/4C+(12/4)

3/4C+3

The -2 comes from multiplying 1/2 *(c-4) which is 1/2C-4/2 or simply 1/2c-2

- math -
**Reiny**, Friday, February 15, 2008 at 10:06amthese questions become easy if you organize your data in a chart form

------------Byte-----Cathy

Age now ---- b ------ c

in 4 yrs -- b+4 ---- c+4

4 yrs ago-- b-4 ---- c-4

so from second line: b+4 = 3/4(c+4)

from third line: b-4 = 1/2(c-4)

These two equations are now easy to simplify and solve giving you the answer provided by drwls above

- math -
**Cathy's cat Byte**, Friday, December 9, 2011 at 2:45amBUTTCHEEKS!!!!!!!

- math -
**Cathy's cat Byte**, Friday, December 9, 2011 at 2:46amBUTTCHEEKS!!!!!!!

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