Posted by Debbie on Thursday, February 14, 2008 at 8:13pm.
If we take the speed of the freight train to be x, and the speed of the passenger train to be y, we get that:
1)y=x+12
2)270/y=210/x
So if we replace y in the second equation by the y we found in the forst equation, we get that:
270/(x+12)=210/x
=>210*(x+12)=270x
=>60x=2520
=>x=42
=>y=54
So the freight train moves at 42mph and the passenger train moves at 54mph
Let the speed of the freight train be x mph
then the speed of the passenger train is x+12 mph
Time for freight train = 210/x
time for passenger train = 270/(x+12)
but they are equal so....
270/(x+12) = 210/x
cross-multiply and solve.
Let me know what you got.
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