The teacher plans to assign 8 students to 8 desks for a debate. How many different seating arrangements are possible?
no its 40,320
Stop trying to answer my questions. Let the professionals help. DO NOT RESPOND AGAIN!!
P.S. - Both your answers were WRONG
To find the number of different seating arrangements for the 8 students, you can use the concept of permutations. In this case, since each student is assigned to one desk, you are looking for the number of permutations of 8 students taken 8 at a time.
The formula for permutations is given by:
P(n, r) = n! / (n - r)!
Where n is the total number of objects and r is the number of objects being arranged.
In this case, n = 8 (students) and r = 8 (desks). Applying the formula, the number of seating arrangements can be calculated as:
P(8, 8) = 8! / (8 - 8)!
Since 8! / 0! is equal to 1, the expression simplifies to:
P(8, 8) = 8! / 1 = 8!
Calculating 8! (8 factorial), we have:
8! = 8 x 7 x 6 x 5 x 4 x 3 x 2 x 1 = 40,320
Therefore, there are 40,320 different seating arrangements possible for the 8 students.
Whenever you read a math question asking how many different arrangements are possible, you simply MULTIPLY what has been given.
In this case, 8 students x 8 desks = 64 possible arrangements.
Done!