Find the molar enthalpy of vaporization for a substance, given that 3.21 mol of the subtance absorbs 28.4 kJ of energy as heat when the substance changes from a liquid to a gas.
28.4 kJ/3.21 mol = ?? kJ/mol.
To find the molar enthalpy of vaporization, we need to divide the heat absorbed by the number of moles of the substance. The formula to calculate the molar enthalpy of vaporization is:
Molar Enthalpy of Vaporization = Heat Absorbed / Number of Moles
In this case, we are given that the substance absorbed 28.4 kJ of energy as heat, and the number of moles is 3.21 mol.
Let's substitute these values into the formula to find the molar enthalpy of vaporization:
Molar Enthalpy of Vaporization = 28.4 kJ / 3.21 mol
Now, we can calculate the molar enthalpy of vaporization:
Molar Enthalpy of Vaporization = 8.86 kJ/mol
Therefore, the molar enthalpy of vaporization for the substance is 8.86 kJ/mol.