Posted by dawn on Wednesday, February 13, 2008 at 4:41pm.
No friction so any work done on it = change in PE + change in KE
Assume both PE and KE are zero at start.
How far up did it go?
h = .5 sin 30 = .25 meters up
How much potential energy did it gain?
PE = m g h = 3.0 * 9.8 * .25 = 7.35 Joules
How much work was done on it
Force in direction of motion = 22 cos 30 = 19.1 N
work done = 19.1 * .5 = 9.53 joules
so
9.53 = KE + 7.35
so
(1/2) m v^2 = 2.18 Joules
I think you can get v from there
Related Questions
Physics - a horizontal force of magnitude 18.0 N is applied to a 3.07 kg book as...
physics - The question is: a horizontal force of magnitude 22.0 N is applied to ...
mary - The question is: a horizontal force of magnitude 22.0 N is applied to a 2...
physices - A physics book slides off a horizontal table top with a speed of 1.30...
physics - a 1.50 kg book is sliding along a rough horizontal surface. At point A...
Physics - A student presses a book between his hands. The forces that he exerts ...
physics, - A student presses a book between his hands The forces that he exerts ...
physics - A student presses a book between his hands, as the drawing indicates. ...
Physics - A student presses a book between his hands, as the drawing indicates. ...
Physics - A physics book slides off a horizontal tabletop with a speed of 1.10m/...
For Further Reading
