Posted by **Jon** on Wednesday, February 13, 2008 at 4:15pm.

1)Find cos theta if sin theta=3/5 and 90 degrees<theta<180 degrees.

A)4/5

B)-4/5

C)square root of 34/5

D)-square root of 34/5

I chose A

2)Simplify:1-csc^2theta/cot^2theta

A)-1

B)1

C)tan^2theta

D)1/sin^4theta

I chose C

3)Simplify:-5(cot^2theta-csc^2theta)

A)5

B)-5

C)-5csc^2 theta

D)5csc^2 theta

I chose B

4)Which expression is not equivalent to 1?

A)sin^2theta+cot^2thetasin^2theta

B)sin^2theta/1-costheta -1

C)sec^2theta+tan^2theta

D)cot^2thetasin^2theta/cos^2theta

I don't know

5)Which expression is equivalent to tan theta-sec theta/sin theta?

A)-cot theta

B)cot theta

C)tan theta-cot theta

D)tan theta-sec^2theta

I don't know

- Math -
**Guido**, Wednesday, February 13, 2008 at 4:18pm
Are you studying for a trig test?

Just curious!

Where is your effort?

Why do you not try to solve each question and show your work?

Then we can help you better.

I would like to know if you are preparing for a math state test.

- Math -
**Jon**, Wednesday, February 13, 2008 at 4:38pm
I have been showing my work in my book but not for these questions b/c I have no clue as to how to solve them its just I need them to be checked and its just too time consuming to post the work on the computer. I really appreciate everyone's help.

- Math -
**Damon**, Wednesday, February 13, 2008 at 7:35pm
I am willing to do one just to show you how. Express all functions as sin and cos, for example tan = sin/cos and then remember that sin^2 + cos^2 = 1

4)Which expression is not equivalent to 1?

A)sin^2theta+cot^2thetasin^2theta

B)sin^2theta/1-costheta -1

C)sec^2theta+tan^2theta

D)cot^2thetasin^2theta/cos^2theta

I don't know

A)--> sin^2 T ( 1 + cos^2 T/sin^2T)

= sin^2T+ cos^2 T = 1

B) --> sin^2 T/(1-cos T) - 1

= sin^2 T (1+cos T)/(1-cos^2T) - 1

= 1 + cos T - 1

this is not 1

C) --> 1/cos^2 T + + sin^2/cos^2 T

= (1+sin^2 T)/cos^2T

that is not 1 either, but I bet you have a typo in the original sign

D) --> cot^2thetasin^2theta/cos^2theta

= (cos^2 T sin^2T)/(sin^2 T cos^2 T)

= 1

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