Posted by Anonymous on Wednesday, February 13, 2008 at 2:38pm.
let [2,8] = a[3,0] + b[-1,2]
so you get 3a - b = 2
and 2b = 8
from the second equation b = 4, subbing that back in to the first...
3a - 4 = 2
a = 2
check to see if [2,8] = 2[3,0] + 4[-1,2]
sure does!
We were lucky that in the second equation one of the variables dropped out, normally you would end up solving 2 equations in 2 unknowns.
What? I don't understand what you did. . .
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