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January 26, 2015

January 26, 2015

Posted by **Jon** on Wednesday, February 13, 2008 at 12:40pm.

A)3/2

B)6

C)4

D)pi/2

I chose B

2)Find the period of y=tan5theta

A)10pi

B)2pi/5

C)5pi

D)pi/5

I chose D

3)Find the phase shift of y=sin(theta-3pi/4).

A)3pi/4

B)-3pi/4

C)4pi/3

D)-4pi/3

I chose A

4)Find the vertical shift of y=-4sec theta+7.

A)-4

B)-7

C)7

D)4

I chose C

5)Find sec theta if tan theta=1/4 and 180 degrees<theta<270 degrees.

A)square root of 15/4

B)-square root of 15/4

C)square root of 17/4

D)-square root of 17/4

I chose C

- math -
**Reiny**, Wednesday, February 13, 2008 at 2:02pmIn #5, the angle is in the third quadrant, so the cosine, and hence the secant, is negative.

sec theta = (-√17)/4

- math -
**Jon**, Wednesday, February 13, 2008 at 2:07pmare the rest ok?

- math -
**Reiny**, Wednesday, February 13, 2008 at 3:20pmyes

- math -

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