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December 19, 2014

December 19, 2014

Posted by **Serena** on Tuesday, February 12, 2008 at 9:16pm.

Can anyone please give me some hints to do this?Thanks a lot!

- physics -
**bobpursley**, Tuesday, February 12, 2008 at 9:47pmThe deltaTemp is (35-0)C.

Q=Area/Thickness*Heatconductivity*deltaTemp

For styrofoam, assume about .03Joules/(sec*m*C)

Solve for q,the amount of heat.

Now, finally a= massice*Lf

- physics -
**Serena**, Tuesday, February 12, 2008 at 10:17pmQ=Area/Thickness*Heatconductivity*deltaTemp

How you get this equation?

and how you use the styrofoam=.03 J/s*m*C?

- physics -

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