Posted by Serena on .
At a picnic, a Styrofoam cup contains lemonade and ice at 0 degree C. The thickness of the cup is 2.0*10^3m, and the area is 0.016m^2. The temperature at the outside surface of the cup is 35 degree C. The latent heat of fusion for ice is 3.35*10^5 J/kg. What mass of ice melts in one hour？
Can anyone please give me some hints to do this?Thanks a lot!

physics 
bobpursley,
The deltaTemp is (350)C.
Q=Area/Thickness*Heatconductivity*deltaTemp
For styrofoam, assume about .03Joules/(sec*m*C)
Solve for q,the amount of heat.
Now, finally a= massice*Lf 
physics 
Serena,
Q=Area/Thickness*Heatconductivity*deltaTemp
How you get this equation?
and how you use the styrofoam=.03 J/s*m*C?