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March 30, 2015

March 30, 2015

Posted by **Spencer** on Tuesday, February 12, 2008 at 11:50am.

- Physics E&M -
**bobpursley**, Tuesday, February 12, 2008 at 12:01pmYou have to measure the area of the cylinder, that is, the outer radius area minus the inner radius.

You are given the mass, you can look up the density.

mass=density*PI(radiusouter^2-radiusinner^2)*length

Now, solve for (radiusouter^2-radiuinner^2)

Areacopper= PI (radiusouter^2-radiusinner^2) or

areacopper= masscopper/(density*lenght)

current= currentdensity*area

So, did the size of the cylinder affect anything?

- Physics E&M -
**Spencer**, Tuesday, February 12, 2008 at 12:55pmThere is no inner or outer im guessing it is assumed to be negligibly thick

- Physics E&M -
**Spencer**, Tuesday, February 12, 2008 at 1:03pmNvm Thank you for the insight into the density. I got the anwser now and your right the radius has nothing to do with it.

- Physics E&M -

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