chemistry
posted by cal on .
What is the sum of the coefficients (including “1”) of the balanced equation?
__CaCO3 + __NaF __ CaF2 + __Na2CO3
4
5
6
7
8
If you start with 20.0 grams CaCO3, how many moles of CaCO3 do you have?
20.0
2.00
.200
.0200
.0386
If you start with .500 moles of NaF, how many moles of CaF2 will form
.500
1.00
1.50
2.00
0.250
What is the sum of the coefficients (including “1”) of the following reaction?
Sodium sulfate + calcium hydroxide ???
4
5
6
7
9
Predict the precipitate that forms: HCl + AgNO 3 ???
HNO3
HCl
AgNO3
AgCl
no precipitate forms

The balanced reaction is
CaCO3 + 2 NaF > CaF2 + Na2CO3
You forgot the reaction arrow.
The sum of the coefficients is 5.
We will be glad to critique your work on the remainder of the problem. I assume you can compute molar mass of a compound and convert mass to moles. 
number 2 is .2 because I found molar mass. Number 3 4 and 5 is where I get lost.

I posted under my friends name accidentally.. but number 2 is .2 because I found molar mass. Number 3 4 and 5 is where I get lost

0.2 is correct for #2.
Here is how you work #3 and all problem similar to it. First, the copy.
CaCO3 + 2NaF ==> CaF2 + Na2CO3
If you start with .500 moles of NaF, how many moles of CaF2 will form
.500
1.00
1.50
2.00
0.250
ASSUMING you have an unlimited supply of CaCO3 (not the 20.0 g in problem 2), convert 0.500 mols NaF to mols CaF2 by using the coefficients in the balanced equation.
0.500 mols NaF x (1 mol CaF2/2 mol NaF) = (notice how the units of NaF cancel and mols CaF2 are leftthis is the way we convert mols of one thing to mols of another) = 0.500 NaF x 1/2 = 0.250 CaF2.
On the others, if you get stuck, repost as a new post (at the top of the board) and tell us exactly what your trouble is in detail. That way we can help you better.