The molecular structure around the oxygen in water is
.
---is the answer bent or angular?
I vote for bent.
either angular or bent is correct.
To determine the molecular structure around the oxygen in water, we can use the concept of VSEPR (Valence Shell Electron Pair Repulsion) theory.
First, we need to determine the Lewis structure of water (H2O). Oxygen (O) has 6 valence electrons, and each hydrogen (H) has 1 valence electron. Therefore, the Lewis structure of water is:
H:O:H
Next, we need to determine the electron pair arrangement. In water, there are two bonded pairs (the two O-H bonds) and two lone pairs on the oxygen atom.
The VSEPR theory states that electron pairs in the valence shell of an atom repel each other and try to maximize their separation. This leads to the predicted molecular geometry.
In the case of water, the electron pairs (bonded and lone pairs) around oxygen repel each other, causing the molecule to adopt a bent or angular shape. The bond angle between the two O-H bonds in water is approximately 104.5 degrees.
So, the correct answer is bent or angular.