Posted by CHLOE on Monday, February 11, 2008 at 6:04pm.
two numbers: x,y
x-y=16
5y=8-3x
u have to solve this system
HOW DO YOU SOLVE 5Y=8-3X? (BIG HELP)
L1: x-y=16
L2: 5y=8-3x
in L1: x=16+y
so in L2 : 5y=8-3*(16+y)=8-48-3y
so 8y=-40
y=-5
in L1 : x-y=16
x-(-5)=16
x=11
if u don't understand this, u have to read your math lesson
THE PRICE OF A SWEATER IS $5 LESS THAN TWICE THE PRICE OF A SHIRT. IF FOUR SWEATERS AND THREE SHIRTS COST $200, FIND THE PRICE OF EACH SHIRT AND EACH SWEATER? HOW DO YOU SET UP THIS PROBLEM?
x=price of a sweater
y=price of a shirt
the system is: x=2y-5
4x+3y=200
so try to solv the system
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