Posted by Anonymous on Monday, February 11, 2008 at 3:41pm.
evaluate integral or state that it is diverges
integral oo, 2 [2/(x^21)] dx

integral oo, 2 [2/(x^21)] dx
Through partial fractions, I came up with lim [ln(x1)ln(x+1)] b, 2
b>oo
I get (ln(3)0)(oooo)). The answer in the back of the book is ln(3). What am I doing wrong?

calculus  H, Monday, February 11, 2008 at 4:25pm
Hi there,
lim [ln(x1)ln(x+1)] b, 2 cannot get (ln(3)0)(oooo)) because ln(00) has no definition. We should make it ln(x1)ln(x+1)=ln[(x1)/(x+1)],then lim[ln[(x1)/(x+1)]]b,2 b>00 is ln(3).

calculus  Keith, Monday, February 11, 2008 at 5:38pm
Using the difference quotient of (x+h)and Evaluate f(x)=(x+y)^3
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