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October 2, 2014

October 2, 2014

Posted by **todd** on Sunday, February 10, 2008 at 10:27pm.

What is the probability that exactly 23 of them are cured?

What is the prob. that more than 23 of them are cured?

What is the prob. that at most 23 of them are cured?

What is the expected # of kids that will be cured using this treatment?

- statistics -
**economyst**, Monday, February 11, 2008 at 9:15amI would solve this problem using basic combinatorial methods. Hint: an EXCEL spreadsheet is very helpful in these types of problems.

The probability that 23 are cured is exactly equal to the probability that 2 are not cured. So, 25-choose-2 is 24*25/2 = 300. So, the probability of seeing exactly 2 not cured is 300*(.9^23)*(.1^2) = 26.588%.

Take it from here to solve the rest of the problems.

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