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March 29, 2015

March 29, 2015

Posted by **Shetina** on Sunday, February 10, 2008 at 10:21pm.

(a) In straight-line distance, how far is city C from city A?

?km

(b) Relative to city A, in what direction is city C?

?° north of west

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**drwls**, Sunday, February 10, 2008 at 11:23pm(a) Add up the x (east) and y (north) component displacement and then compute the magnitude of the resultant.

X = -200 - 260 cos 32

Y = 260 sin 32

distance = sqrt (X^2 + Y^2)

(b) The direction is in the second quadrant, since X is negative and Y is positive. If A is the angle north from west, A = arctan (-Y/X)

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**Shetina**, Monday, February 11, 2008 at 7:26pmthank you for the help....but still could not figure out the answer

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- physics -
**Anonymous**, Wednesday, December 4, 2013 at 3:26pma) 484km

b) 18 degrees nw

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