Posted by Shetina on Sunday, February 10, 2008 at 10:21pm.
(a) Add up the x (east) and y (north) component displacement and then compute the magnitude of the resultant.
X = -200 - 260 cos 32
Y = 260 sin 32
distance = sqrt (X^2 + Y^2)
(b) The direction is in the second quadrant, since X is negative and Y is positive. If A is the angle north from west, A = arctan (-Y/X)
thank you for the help....but still could not figure out the answer
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