Post a New Question

physics

posted by .

There is a 0.225 T magnetic field directed along the +x axis and a field of unknown magnitude along the +y axis. A particle carrying a charge of 7.20 10-5 C experiences a maximum force of 0.455 N when traveling at a speed of 2 104 m/s through the region where the fields are. Find the magnitude of the unknown field.

  • physics -

    Do you mean V = 2*10^4 ???

    F = q ( V x B )
    the force is maximum when the velocity vector is perpendicular to the B fieldso consider the B field in the x y plane and V in the z direction.
    then
    |F| = |q| |V| |B|
    so
    .455 = 7.210^-5 * 2 * 10^4 * |B|
    |B| = .316 T
    so
    Bx^2 + By^2 = |B|^2 = 0.1 T
    .225^2 + By^2 = .1
    .05 + By^2 = .1
    so By is also about .22 T

  • physics -

    where did you get .1 from?

  • physics -

    The .1 is from |B|^2 which is equal to .316^2

Answer This Question

First Name:
School Subject:
Answer:

Related Questions

More Related Questions

Post a New Question