Posted by **mhaidar9108** on Friday, February 8, 2008 at 11:41pm.

How much heat must be added to 50.0g of aluminum metal at 25 degrees C to raise its temperature to 125 degrees C?

I have about 20 of these left so if you can do this and work it out and show me how you did it it would be great so I can use it as a guide for the next 19. Thanks.

- chemistry Ap -
**drbob222**, Saturday, February 9, 2008 at 12:35am
q = mass x specific heat x (Tf - Ti).

q = 50.0 g x specific heat Al x (125-25).

You will need to look up the specific heat of Al metal. The units should be in Joules/gram. If the units are in J/mol, then you must change the 50.0 g Al to mols Al by dividing 50 by atomic mass Al. Tf is the final T and Ti is initial T in these calculations. You also may have some change of state (e.g. solid to liquid (melting) or liquid to gas (boiling) problems. These are done by

q = mass x heat fusion (for melting)

q = mass x heat of vaporizaton (for boiling). Of course they may be the reverse, also, (opposite of boiling is condensation and opposite of melting is freezing) but those are done exactly the same except the sign is reversed. Heat goes in (plus sign) for melting or boiling and heat goes out (negative sign) for freezing or condensation. Good luck.

- chemistry Ap -
**mhaidar9108**, Saturday, February 9, 2008 at 12:40am
ty or this. I tried this al land my answer came to q=24,000 joules. Is this correct...

- chemistry Ap -
**drbob222**, Saturday, February 9, 2008 at 10:23am
I looked up Al and found the specific heat to be 0.900 J/g*C.

So 50.0 x 0.900 x 100 = 4500 J.

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