posted by Mandi on .
Can you tell me if I have the correct answer?
How much heat is required to convert 0.3 kilogram of ice at 0 degrees celsius to water at the same temperature?
Close but I don't know what you used for the heat of fusion.
I have 334 J/g for ice and 0.3 kg = 300 g; therefore, 334 x 300 = 100,200 J.
If I use 80 calories/g, then
80 x 300 = 24,000 calories and convert that to J (x 4.184) = 100,416. So your answer is in the ball park.