Posted by Mandi on Thursday, February 7, 2008 at 11:49pm.
Close but I don't know what you used for the heat of fusion.
I have 334 J/g for ice and 0.3 kg = 300 g; therefore, 334 x 300 = 100,200 J.
If I use 80 calories/g, then
80 x 300 = 24,000 calories and convert that to J (x 4.184) = 100,416. So your answer is in the ball park.
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