A solution contains 0.0653g of compound in 8.31g of ethanol. The molarity of the solution is 0.0368m. Calculate the molecular weight of the compound

214 g/mol

sorry my fault it is suppose to be molality

I think you MUST have meant molality.

molality = mols/kg solvent
0.0368 m = mols/0.00831 kg.
Solve for mols = 0.0368 x 0.00831
mols = g/molar mass
You know mols and g, solve for molar mass.

To calculate the molecular weight of the compound, we can rearrange the formula for molarity:

Molarity (M) = moles of solute / volume of solution (in liters)

In this case, we know the molarity is 0.0368 M, and we have 8.31 grams of ethanol as the volume of the solution.

To find the moles of solute, we can use the formula:

moles of solute = mass of solute / molar mass of solute

In this case, the mass of solute is 0.0653 grams, and we want to find the molar mass of the compound.

Rearranging the formula for moles of solute gives us:

molar mass of solute = mass of solute / moles of solute

Plugging in the values we know:

moles of solute = 0.0653 g / molar mass of solute

Now we can substitute this value into our equation for molarity:

0.0368 M = (0.0653 g / molar mass of solute) / 8.31 L

To solve for the molar mass of the solute, we can rearrange the equation:

molar mass of solute = (0.0653 g / 0.0368 M) * 8.31 L

Now, we can calculate the value of the molar mass of the solute by plugging in the known values:

molar mass of solute = (0.0653 g / 0.0368 mol/L) * 8.31 L

molar mass of solute = 112.27 g/mol

Therefore, the molecular weight of the compound is 112.27 g/mol.

The molarity of the solution can't be 0.0368 m. It can be 0.0368 molar or it can be 0.0368 molal. Which is it.