Citric acid H3C6H5O7, occurs in plants. Lemons contain 5% to 8% citric acid by mass. The acid is added to beverages and candy. An aqueous solution is 0.688m citric acid. The density is 1.049 g/ml. What is the molar concentration?

.722 mols/L

don't forget when finding the mass for the volume equation you must add the mass of your solute, citric acid. once you find the total mass, then divide by the density to give you the total volume. Then moles of citric acid divided by your total volume gives you the molarity, aka molar concentration.

To find the molar concentration of an aqueous solution, we need to first determine the number of moles of the solute (in this case, citric acid) and then divide it by the volume of the solution in liters.

Given information:
Mass percentage of citric acid in lemons = 5% to 8%
Aqueous solution of citric acid = 0.688 M
Density of solution = 1.049 g/mL

To determine the molar concentration, we will first calculate the number of moles of citric acid using the given information.

1. Calculate the mass of citric acid in the solution:
Since the density of the solution is given as 1.049 g/mL and the solution is in milliliters, we can use the formula: mass = density × volume.

Assuming we have 1 L (1000 mL) of solution:
mass = 1.049 g/mL × 1000 mL
mass = 1049 g

2. Calculate the number of moles of citric acid:
To calculate the number of moles, we need to know the molar mass of citric acid, which is found by summing up the atomic masses of its constituent elements (H: 1.01 g/mol, C: 12.01 g/mol, and O: 16.00 g/mol).
The molecular formula of citric acid, H₃C₆H₅O₇, indicates that it contains:
3 H atoms: 3 × 1.01 = 3.03 g/mol
6 C atoms: 6 × 12.01 = 72.06 g/mol
7 O atoms: 7 × 16.00 = 112.00 g/mol

Molar mass of citric acid = 3.03 g/mol + 72.06 g/mol + 112.00 g/mol ≈ 187.09 g/mol

Now, we can calculate the number of moles of citric acid:
moles = mass / molar mass
moles = 1049 g / 187.09 g/mol ≈ 5.60 mol

3. Calculate the molar concentration:
Molar concentration (Molarity) is defined as the number of moles of solute divided by the volume of the solution in liters.
Given that the aqueous solution of citric acid is 0.688 M, we can infer that there are 0.688 moles of citric acid in 1 liter of solution.

Therefore, the molar concentration of the citric acid solution is approximately 0.688 M.

m = mols/kg solvent

1 kg solvent has a mass of 1,000 g and a volume of v = m/d = 1000/1.049 = 953.3 mL or 0.9533 liters. Then Molarity = mols/L. You have 0.688 mols and you have 0.9533 L so the molarity = ??
check my thinking.