Find the equation of the tangent line
5x^2+y^2=14 at (1,3).
P.S: It's calculus.
So far I know this much
(dy/dx)= -10x/2y= -5x/y
m= -5(1)/3= -5/3
3= -5/3(1)+b then what?
Math - Reiny, Thursday, February 7, 2008 at 5:35pm
ahh, so close!
solve for b in your last equation
I get b = 14/3
put m and b into your y = mx + b and you are done