Posted by **Skye** on Thursday, February 7, 2008 at 5:27pm.

Find the equation of the tangent line

5x^2+y^2=14 at (1,3).

P.S: It's calculus.

So far I know this much

10x+2y(dy/dx)=o

-10x -10x

___________________

2y(dy/dx)= -10x

(dy/dx)= -10x/2y= -5x/y

m= -5(1)/3= -5/3

y=mx+b

3= -5/3(1)+b then what?

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