Posted by **Jon** on Thursday, February 7, 2008 at 10:17am.

1)Two marbles are chosen at random from a bag containing 3 blue and 2 red marbles. The relative-frequency histogram shows the distribution of the number of red marbles chosen. Find P(0 red). (the gragh shows 3/10 for 0 red, 3/5 for 1 red, and 1/10 for 2 red)

A)0

B)8/15

C)3/10

D)2/5

I chose C

2)A red die and a blue die are tossed. What is the probability that the red die shows a 3 and the blue die shows a number greater than 3?

A)1/10

B)1/5

C)1/12

D)3/5

I chose C

3)Tickets are numbered 1 to 50 and placed in a box. Three tickets are drawn at random without replacement. What is the probability that their numbers are all greater than 25?

A)1/8

B)23/196

C)69/625

D)1/2

I chose D

4)From 4 yellow and 8 blue marbles, 3 are selected. What is the probability that all 3 are yellow or all 3 are blue.

A)3/11

B)1/55

C)14/55

D)3/220

I don't know I GUESS A

5)A card is drawn from a standard deck of cards. What is P(heart or a 6)?

A)9/26

B)17/52

C)1/4

D)4/13

I chose B

- Probability (#5 of 5) -
**drwls**, Thursday, February 7, 2008 at 10:29am
5) There are 13 hearts and 3 sixes that are not hearts. You can't count the six of hearts twice. That makes 16/52. Which fraction choice is that?

- Probability/Statistics -
**Reiny**, Thursday, February 7, 2008 at 10:43am
1 and 2 are correct

for 3 I got 23/196

there are 25 tickets greater than 25

so prob = 25/50 x 24/49 x 23/48 = 23/196

for 4 you have to use a formula that says:

P(A or B) =P(A) + P(B) - P(A and B)

since the prob of them being 3 yellow AND 3 blue is zero

P(3yellow) = 4/12 x 3/11 x 2/10 = 1/55

P(3blue) = 8/12 x 7/11 x 6/10 = 14/55

so your prob = 1/55 + 14/55 = 3/11

GOOD GUESS

#5 (use the same formula as #4)

prob(heart) = 13/52

Prob(6) = 4/52

Prob(6of hearts) = 1/52

so prob(heart OR a 6) = 13/52 + 4/52 - 1/52

= 16/52

= 4/13

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